Civil Engineering PE

Category - Transportation

The decision sight distance for a rural roadway with a speed of 50 miles per hour (mph) and a maneuver A is which of the following?
  1. 230.2 feet
  2. 460.5 feet
  3. 908.8 feet
  4. Not enough information provided
Explanation
Answer: B - The decision sight distance for a rural roadway with a speed of 50 miles per hour (mph) and a maneuver A is 460.5 feet.

Solution: Use the Decision sight distance equation (Maneuver A)

d = 1.47Vt + 1.075V2/a

Where t = 3.0 seconds

V = 50 mph

a = 11.2 ft/s2

d = 1.47(50) (3)+ 1.075(50)2/11.2

= 220.5 + 240 = 460.5 feet
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