Civil Engineering PE

Answer: B - The outlet velocity of a vented tank that is 15 meters high is approximately 17.2 meters/second.

Solution: Use Bernoulli equation to solve for outlet velocity.

g*h₁ + (p1/p) + (V₁²/2) = g*h₂ + (p2/p) + (V₂²/2)

In the case of a vented tank, the pressure inside and outside of the tank can be assumed to be the same. Bernoulli’s equation can be transformed and used to solve for the outlet velocity (V₂) as follows:

V₂ = (2*g*h)^1/2

Given g = 9.81 meters/second²

V₂ = (2*9.81 meters/second² *15 meters)^1/2

= 17.2 meters/second