Civil Engineering PE

Category - Transportation

What is the approximate distance traveled by a vehicle decelerating from 65 miles per hour (mph) to 35 mph at a rate of 3 feet per second/second?
  1. 900 feet
  2. 1,070 feet
  3. 1,634 feet
  4. None of the above
Explanation
Answer: B - The approximate distance traveled by a vehicle decelerating from 65 miles per hour (mph) to 35 mph at a rate of 3 feet per second/second is 1,070 feet.

Solution: use the distance traveled equation

x = vf2 - vo2 / 2a

Where

vf = 65 mph * (5280 feet/mile) (1 hour/3600 seconds) = 95 feet per second

vo = 35 mph * (5280 feet/mile) (1 hour/3600 seconds) = 51 feet per second

a = 3 feet/second/second

x = (952 - 512)/ 2(3)

x = 1,070 feet (approximate)
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