Answer: .0979 gramsBegin by converting 1.34x1021 molecules into moles using Avogadro’s number. Once this value is obtained, use the molar mass of CO2 to convert to grams. The expression appears as follows, 1.34x1021 molecules x (1 mol / 6.022x1023) x (44.009 grams / 1 mol) = .0979 grams.

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Praxis II: Chemistry Exam Prep

Category - Chemistry

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What is the mass in grams of 1.34x1021 molecules of CO₂?

.0979 grams
9.79 grams
.00223 grams
.223 grams
44.0 grams

Explanation

Answer: .0979 grams

Begin by converting 1.34x10²¹molecules into moles using Avogadro’s number. Once this value is obtained, use the molar mass of CO₂to convert to grams. The expression appears as follows, 1.34x10²¹molecules x (1 mol / 6.022x10²³) x (44.009 grams / 1 mol) = .0979 grams.

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