Given a triangle with sides a = 20 feet, b = 40 feet, and c = 56, what is the area in square feet?
  1. 71.67 ft2
  2. 116.00 ft2
  3. 281.68 ft2
  4. None of the above
Explanation
Answer: C - The area of the triangle is 281.68 ft2.

Solution

Use the formula for the area of a triangle with sides a, b, and c:

A = [s(s-a)(s-b)(s-c)]½ where s = (a + b + c)/2

Where a = 20 ft
b = 40 ft
c = 56 ft

s = (20 ft + 40 ft + 56 ft)/2 = 58 ft

A = [58 (58-20)(58 - 40)(58 - 56)]½= 281.68 ft2
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