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SAT Chemistry

Category - Multiple Choice

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1.75 moles of NaCl are dissolved in 1.00 kg of water. What is the boiling point of this solution (k_b= .512 degrees C·kg/mol for water)?

101.79 degrees Celsius
100.00 degrees Celsius
98.21 degrees Celsius
102.22 degrees Celsius
100.50 degrees Celsius

Explanation

Answer: 101.79 degrees Celsius

This problem addresses the colligative property of boiling point elevation. Ionic solids raise the boiling point of a solution according to the formula (change in boiling point) = m x k_b x i. In this case, i takes a value of two, since two ions form from every molecule of solid NaCl. Plugging in for the variables indicates that the correct boiling point for this solution is 101.79 degrees Celsius.

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