Answer: A - 0.66g dissolved at a concentration of 0.013 g/mL are dissolved. The solution is as follows:C = concentration (g/mL)P = pressure (atm)C1/P1 = C2/P2C1=.5g/50mL = .01g/mLP1=1.0 atmC2 = ?P2 = 1000 mmHg * 1 atm/760mmHg = 1.32atm(.01g/mL)/(1.0atm) = C2/(1.32atm)C2= .013g/mLAt V = 50mL, this means there are 0.013g/mL * 50mL = 0.66g dissolved.

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IB Chemistry Test Prep

Category - IB Chemistry

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You are dissolving a gas in water. If the partial pressure of the gas is 1 atm, and the concentration is .5g per 50mL of solution, then what is the concentration of gas at 800mmHg? How many grams of gas are dissolved in the water now?

0.66g dissolved at a concentration of 0.013 g/mL
0.66 g dissolved at a concentration of 0.02 g/mL
0.5 g dissolved at a concentration of 0.013 g/mL
0.5 g dissolved at a concentration of 0.02 g/mL
1.0 g dissolved at a concentration of 0.02 g/mL

Explanation

Answer: A - 0.66g dissolved at a concentration of 0.013 g/mL are dissolved.

The solution is as follows:

C = concentration (g/mL)
P = pressure (atm)
C1/P1 = C2/P2

C₁=.5g/50mL = .01g/mL
P₁=1.0 atm
C₂ = ?
P₂ = 1000 mmHg * 1 atm/760mmHg = 1.32atm

(.01g/mL)/(1.0atm) = C₂/(1.32atm)
C₂= .013g/mL

At V = 50mL, this means there are 0.013g/mL * 50mL = 0.66g dissolved.

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