FE Civil Engineering Exam Prep

Category - Civil Engineering

What is the passing sight distance for a section of 60 mile per hour (mph) 2-lane rural highway with a 1740-foot vertical sag curve where a bridge passes over at 16.8 feet? (Assume S > L and A = 3.15)
  1. 870 feet
  2. 2,210 feet
  3. 2,273 feet
  4. 3,389 feet
Explanation
Answer: C - The passing sight distance for a section of 60 mph 2-lane rural highway with a 1,740-foot vertical sag curve where a bridge passes over at 16.8 feet is 2,273 feet.

Solution: Use sag vertical curve length at undercrossing equation (US Customary units)

S = L/2 + 400(C-5.75)/A

Where, L = 1740 feet

C = 16.8

A = 3.15

S = 1740/2 + 400(16.8-5.75)/3.15

= 2,273 feet
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