If the father's blood type is AB and the mother's blood type is homozygous B, what is the percent likelihood that their offspring will exhibit type B?
Explanation
Answer: C. There is a two out of four chance that the child will have the B blood type.
Key takeaway: Using the Punnett square, it is immediately evident that the child will only have B or AB type blood. The father can donate either an A allele or a B allele whereas the mother can only donate a B allele. Therefore, there is a 50% chance the child will have B-B alleles, and the B blood type, and a 50% chance of A-B alleles, and the AB blood type.
