Practice Quiz

SAT Math

Category - Algebra and Functions

Start a Study Session Sign up for Question of the Day
Which of the following quadratic equations has solutions x_1 = − 3 and x_2 = 4?
  1. x^2 + x − 12 = 0
  2. x^2 − x − 12 = 0
  3. x^2 + x + 12 = 0
  4. x^2 − x + 12 = 0
  5. − x^2 + x − 12 = 0
Explanation
Answer: B - The quadratic equation with solutions − 3 and 4 is x^2 − x − 12 = 0. If x_1 and x_2 are the solutions of the quadratic equation, then the quadratic equation can be written in the form (x − x_1 )(x − x_2).
(x − x_1 )(x − x_2 ) = (x-3)(x − 4) = (x + 3)(x − 4) = x^2 − 4x + 3x − 12 = x^2 − x − 12
So, the quadratic equation whose solutions are − 3 and 4 is x^2 − x − 12 = 0.
Previous Next
Was this helpful? Upvote!
Login to contribute your own answer or details
Start a Study Session Sign up for Question of the Day

Top questions

Related questions

Most popular on PracticeQuiz