Answer: BH3NH3 has three bonding hydrogens and a lone pair of electrons, giving it trigonal pyramidal geometry. XeO4 has four bonding oxygens and thus tetrahedral geometry. Similarly, CH4 has four bonding hydrogens and tetrahedral geometry. SiF6 has six bonding flourines, and octahedral geometry. BH3 has just three bonding hydrogens and no lone pairs of electrons, therefore displaying trigonal planar geometry.

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SAT II Chemistry Exam Prep

Category - Multiple Choice

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Which of the following molecules displays planar geometry?

NH₃
BH₃
XeO₄
CH₄
SiF₆

Explanation

Answer: BH₃

NH₃ has three bonding hydrogens and a lone pair of electrons, giving it trigonal pyramidal geometry. XeO₄has four bonding oxygens and thus tetrahedral geometry. Similarly, CH₄has four bonding hydrogens and tetrahedral geometry. SiF₆has six bonding flourines, and octahedral geometry. BH₃has just three bonding hydrogens and no lone pairs of electrons, therefore displaying trigonal planar geometry.

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