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Praxis II General Science

Category - Physics

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What is the capacitance of a capacitor with an area of 500 cm² and a distance between plates of 0.01 cm? Coulomb’s constant is given as 8.85 x 10^-12

0.004 μF
0.008 μF
0.012 μF
0.55 μF
0.85 μF

Explanation

Answer: A - The capacitance is 0.004 μF. C = e*(A/d), where e is Coulomb’s constant, A is the area, and d is the distance between the two plates. For this problem, we need to convert the area into 0.05 m² (keeping in mind 1 m² is 100,000 cm²).

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