Answer: C - It will need to be approximately 7.5 m2. 5x40 watts = 200 watts needed. With the efficiency of 15%, 1m2 will produce 27 watts. Thus, 200/27 = 7.41, or about 7.5 m2 of solar panel needed.

PracticeQuiz content is free on an ad-supported model.

Unfortunately, we can't support ad blocker usage because of the impact on our servers. If you'd like to continue, please disable your ad blocker and reload page.

Reload page

Praxis II General Science

Category - Physics

Start a Study Session Sign up for Question of the Day

Solar panels are an environmentally-friendly way of producing electricity. Modern solar panels can reach 15% efficiency for converting light into electricity. In Washington, the average sunlight is about 180 W/m². If someone wants a solar panel capable of powering five 40-watt lights, how big will it need to be?

2 m²
4.5 m²
7.5 m²
10 m²
15 m²

Explanation

Answer: C - It will need to be approximately 7.5 m². 5x40 watts = 200 watts needed. With the efficiency of 15%, 1m² will produce 27 watts. Thus, 200/27 = 7.41, or about 7.5 m² of solar panel needed.

Was this helpful? Upvote!

Start a Study Session Sign up for Question of the Day

Praxis II General Science

Top questions

Related questions

Most popular on PracticeQuiz

Ad-Blocker not supported

Praxis II General Science

Top questions

Related questions

Most popular on PracticeQuiz