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Praxis II General Science

Category - Physics

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If a magnetic field of 10 x 10^-5 T is applied perpendicularly to a 1 meter wire carrying 5 amps of current, what will be the force experienced by the wire?

0.0000085 N
0.00005 N
0.095 N
0.135 N
0.875 N

Explanation

Answer: B - The force experienced will be 0.00005 N. The force generated by a magnetic field on a current carrying wire is F = I*L*B*sin(θ). Because the field is perpendicular, sin(θ) is 1. Thus, F = 5*1*10x10^-5, or approximately 0.00005 Newtons.

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